![]() 12/12/2017 at 13:22 • Filed to: None | ![]() | ![]() |
Is it torque or something else? And if so, can you derive anything from that? (pun fully intended.)
![]() 12/12/2017 at 13:25 |
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This is a math joke. I don’t get those.
![]() 12/12/2017 at 13:26 |
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Semi related: how about the integral of the power curve to show the area under the curve? Then you could more accurately compare a big NA V8 with a high-revving I4 using a much better metric than peak bhp.
Not my original idea, I think I read it on Jalop about 10 years ago.
/opening a Calculus tutoring franchise called DeriveTime
![]() 12/12/2017 at 13:28 |
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Hammerheadfistpunch has talked extensively about this very subject.
![]() 12/12/2017 at 13:30 |
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Force Per unit time. 1 HP is 550 ft-lbs/s.
![]() 12/12/2017 at 13:32 |
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A derivative is just the tangential line to a point. Although I probably worded that so that it didn’t make sense.
![]() 12/12/2017 at 13:33 |
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But it’s the tangential line at a point, AT EVERY POINT, which makes another line....or a lot of lines....
![]() 12/12/2017 at 13:34 |
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cept the math bit. I could never into math, which is why I was a communications major! But yeah, average power would be a great way to compare. Sadly no one publishes power charts...except GM for some reason.
![]() 12/12/2017 at 13:34 |
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That’s an awesome idea! I wonder if you could also use that with gear ratios to figure which car will have the most torque/horsepower at the wheels?
![]() 12/12/2017 at 13:34 |
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Please stop drinking before you derive again ....
![]() 12/12/2017 at 13:37 |
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It is a fantastic way to see how useful the powerband is for normal driving conditions. It would show that an RX8 sucks and a Ford with a 24v V6 is much easier to drive.
![]() 12/12/2017 at 13:38 |
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I think we need to spam David Tracey’s email until he does an article comparing some motors this way.
![]() 12/12/2017 at 13:45 |
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This really gets into partial differential equations.
Depends. HP = Torque*RPM/5252.
If you take the derivative of HP with respect to RPM dHP=(RPM*Torque/5252)dRPM would be HP’=Torque/5252
However if you take the derivative of HP with respect to and arbitrary variable, say x. Then dHP=RPM*Torque/5252dx would be 0.
I’m not sure how useful those would be. You could do dHP=RPM*Torque/5252dTorque would be HP’=RPM/5252.
You could do dHP=RPM*Torque/5252dRPMdTorque. But I think that gets to a constant of 1/5252.
It’s been awhile since partial differential equations, so I’ll need someone to check my work.
![]() 12/12/2017 at 13:54 |
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The time rate of change of the ratio of the horsepower to the rpm.
How quickly your horsepower:rpm changes, not very useful.
![]() 12/12/2017 at 14:29 |
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I derive pleasure from it.
![]() 12/12/2017 at 17:38 |
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Turbo lag.